physics
... 9.8 The same is done for the tension in the rope for the next two trials. Method Linear mass density % Difference Direct 0.0039 ----------- Frequency vs. n Tension = 0.0017 99 % Frequency vs. n Tension = 0.000876 98% Frequency vs. n Tension = 0.000613 99% The direct linear mass density was obtained by m = mass/length m = 0.0225 kg / 5.67 m = 0.0039 To acquire tension, first the slope of the line must be found, using slope = Dn2/Df2 Trial 1: 52-12/362-82= 0.019 Trial 2: 52-12/502-92 = 0.010 Trial 3: 52-12/602-122 = 0.007 Now apply the formula T = (4l2)m(f2/n2) Trial 1 will look like this: T = (4)(2.372)(0.0039)(0.019) T = 0.0017 Since direct linear mass density is found by mass/length, we divide the mass in Trial 1 (.55kg) by the length of the string (2.37m) to get 0.232. This is the actual value. Then the percent difference is computed by % = |Theoretical – Actual| / Actual * 100% % = |0.0017 – 0.232| / 0.232 *100 = 99 Trial 2: 1.05/2.37 = 0.443 % = |0.000876- 0.443| / 0.443 *100 = 98 Trial 3: 1.55/2.37 = 0.654 % = |0.000613 – 0.654| / 0.654 *100 = 99 Conclusion: A: This lab shows students that when a string possesses a certain tension and frequency is applied to it, there will be a variable number of vibrating segments. The lab made it evident that the higher the f...