chemistry
...hen the Calcium Oxide has reacted with the Hydrochloric Acid for one minute, there is an increase in temperature of 13.6°C. From the results of the experiment, the enthalpy change can be calculated. The equation mcDT can be used to calculate the correct enthalpy of change. Energy transferred by CaCO3 + HCl Mass of water = 25g Specific heat capacity = 4.2 Raise in temperature = (23.2-17.7) = 5.5°C Mass of CaCO3 = 1.4g mcDT = 25 x 4.2 x 5.5 = 577.5 J This is the energy transferred through burning 1.4g of CaCO3. The mass of 1 mole of CaCO3 is (40+12+16+16+16) 100g. Enthalpy change = 577.5 x (100/1.4) = 41250 KJ mol-1 From this experiment the value for DH°C (CaCO3) is – 41250 KJ mol-1 Energy transferred by CaO + HCl Mass of water = 30g Specific heat capacity = 4.2 Raise in temperature = (34.3-19.8) = 14.5° Mass of CaCO3 = 1.2g mcDT = 30 x 4.2 x 14.5 = 1827 J This is the energy transferred through burning 1.2g of CaO. The mass of 1 mole of CaO is (40...